National Testing Agency (NTA) has released the CSIR NET admit card 2019 today, at 6 pm. Candidates who have applied for the Joint CSIR UGC NET December 2019 exam can now download their admit card from csirnet.nta.nic.in.
Where to download CSIR NET Admit Card 2019 from?
The official website of the exam is csirnet.nta.nic.in. It is from there that candidates have to download the admit card.
How to download CSIR NET Admit Card December 2019?
The first thing to download is to go to csirnet.nta.nic.in. Then on the main page, you will find the link flashing “Download Admit Card”. Click on the link, a new window gets open. There, enter the application number, password, and security pin. Submitting these lead to the candidate dashboard.
On the candidate dashboard, locate the admit card download link. Clicking which leads to verification of details page. On this page too locate download link, which finally downloads the admit card in device, as a pdf file.
For login into the account, candidates need their application number and password. If it may happen that they have forgotten either of the one, then they can click on the “forgot password” and “forgot application number” link provided there. Clicking on either will be ways to retrieve your lost application number and change your password. Follow the steps and retrieve the credentials.
What details to check in the admit card?
In the admit card there are several details which make the admit card authentic and reliable proof to allow the candidate to appear in the examination. Candidates must check the details. These are, the name of a candidate, exam date, roll number, exam centre, venue code /centre code, exam timings, candidate photograph, candidate signature, instructions for the exam and the medium of the exam.
What to do if there is a discrepancy in the CSIR NET admit card?
Candidates who come across discrepancy in photograph or signature in admit card, need to contact the NTA CSIR NET helpline between November 9, 2019, and November 16, 2019. The helpline can be reached out on these dates from 10 am to 5 pm. In such cases NTA shall allow candidates to appear for exam with that admit card only, but edit details later.
This test is being conducted to test the eligibility for the junior research fellowship (JRF) and for Lectureship (LP)/ assistant professorship in Indian universities and colleges. The test has been scheduled to be held on December 15, 2019. The exam will happen in two shifts one in the morning from 9:30 AM to 12:30 PM and other in the afternoon starting from 2:30 PM till 5:30 PM.
The exam scheduled will be held in an online mode i.e a computer-based test. It will be a total of 3 hours containing all the objective types of questions.. The subjects for which this is happening are life sciences, physical sciences, chemical sciences, earth science and mathematical sciences. For each subject mentioned there are 3 parts in the paper having a different total number of questions and marking scheme.
Chemical sciences have a total of 120 questions, earth sciences papers have a total of 150 questions, for life sciences, the number is 145, in mathematical sciences paper the total questions are 120 and the number of questions in the physical sciences paper is 75.
NTA is established by human resource development, the government of India to conduct efficient and transparent exams with proper test standards to assess the competency of candidates for admission. National Testing Agency (NTA) is the body which entrusted with the responsibility to conduct the CSIR NET fellowship exam by the Council of Scientific and Industrial Research (CSIR). This exam is being conducted to select the candidates for the Junior Research Fellowship (JRF) and for Lectureship (LS) /Assistant Professorship’ in Indian universities and colleges. These fellowships are provided for the research methods training under the supervision of guidance woking in various fields of sciences.
