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Home » Bihar STET 2019 Exam Date Announced; Application Form Releasing on 9 September

Bihar STET 2019 Exam Date Announced; Application Form Releasing on 9 September

You will get only nine days to fill the application form of Bihar State Teacher Eligibility Test 2019.

by Anwesha Bose
September 7, 2019
in Uncategorized
Reading Time: 2 mins read
Bihar STET 2019

Bihar State Teacher Eligibility Test (STET) 2019 exam date was announced today in a press conference by BSEB Chairman, Shri Anand Kishore. As per the announcement, BSEB will conduct Bihar STET on November 7, 2019. On the same day, the exam for physical teachers will also be held.

The application form for Bihar STET 2019 will be available from Monday, September 9, 2019. Last date to apply online will be Wednesday, September 18, 2019. Bihar School Education Board has created a new website bsebstet2019.in for inviting online application form from candidates, and on this website only all updates about the teacher eligibility test will be updated. Candidates may note that right now the website is not working. However it will be launched in coming two days.

The number of vacancies for madhyamik that is classes 9th and 10th, and uchha madhyamik that is classes 11th and 12th are respectively announced as 25,270 and 12,065. These vacancies are in seven subjects for each class. For madhyamik, the subjects are english, hindi, science, social science, hindi, sanskrit, urdu. Whereas the uchha madhyamik subjects are english, mathematics, physics, chemistry, zoology, botany, computer science.

Anand Kishore confirms that there are several changes in the Bihar STET 2019 as compared to previous Bihar TETs. Until now candidates who got minimum marks in the exam were declared qualified, and they could then take part in Bihar teacher niyojan. This time the cut off in Bihar STET exam 2019 will be 50% for general candidates. It will be 45% for SC, ST, PWD, female. This time the change is that after the exam, merit list will be created for all candidates who get marks more than cut off. After that Bihar School Examination Board will declare result of only as many number of candidates who have scored marks more than cut off. 

Tie breaking will be on the basis of age, that is older candidates will get a higher rank. If tie does not break according to age then candidates with more marks in qualifying exam will get the higher rank in merit list. Finally, alphabetically rank will be done. This way the BSEB TET 2019 result will be announced.

The exam will have multiple choice questions with four options in each question. There will not be any negative marking in the exam. There will be 150 questions in paper 1 for madhyamik teachers, as well as paper 2 for uchha madhyamik teachers. In both papers, 100 questions will be related to the subject, and 50 will be related to teaching methodology. 

Paper 1 eligibility criteria is that candidate must have graduation in the subject, and should have B.Ed. For paper 2, candidate should have post graduation in the subject and have B.Ed. However for computer science subject, B.Ed is not compulsory. More details about the exam will be updated in some time.

Tags: BiharBihar STETBihar STET 2019Bihar TETBihar TET 2019bsebstet2019.in
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