NTA successfully conducted JEE Main 2019 again on the second day. Today Paper 1 was held in both shifts. As per students, Mathematics was toughest in shift 1, and Physics was toughest in shift 2. Chemistry was easiest in both. Each shift had a different question distribution. Now that exam is over, students can check JEE Main 2019 analysis, question paper, answer key that is memory based.
Since the exam is taking place on different days – 8, 9, 10, 11, 12 January – therefore students of upcoming exam dates are eagerly looking for question papers of exams that have concluded. Several institutes and individuals are sharing memory based questions which are compiled at JEE Main 2019 Question Paper. One by one, their answers are also being updated.
Overall as well as section wise analysis of JEE Main 2019 have been published online. Going through it throws light upon difficulty level indicating whether students should expect cut off to go higher or lower. As far as Day 2 (January 9) is concerned, both shifts were of same difficulty level as of last year. Hence any major flutter is not anticipated in cut off.
AglaSem is publishing day wise, shift wise JEE Main 2019 question paper, answer key, analysis (check here). Students can access the same for each day after that day’s exam is over. Question papers are currently memory based. NTA is expected to publish official question paper with answer key by January 19, 2019.
JEE Main 2019 (January 9) Shift 1 was held today from 9:30 am to 12:30 pm. According to the students who appeared for the exam in shift 1, questions were formula focused. The exam was not lengthy. But the questions were a bit difficult. Among all the sections, the questions of Mathematics were the toughest. However, The section of Physics was moderate to difficult. But this section was quite lengthy. Questions were also asked from the previous years’ question papers. The overall questions were asked from class 11 rather than class 12.
In the shift 2, Physics section was difficult and lengthy. Chemistry and Mathematics easy. However, this time, the section of Maths was lengthy. The overall questions were tough as compared to the previous years’ questions.
In JEE Main 2019 exam the candidates can opt between two papers. The paper I has 90 questions of 360 marks, i.e. each correct answer will give 04 marks. The questions are asked from Physics, Chemistry, and Mathematics. The paper II of JEE main has questions from Maths, General Aptitude, and Drawing questions (Non-MCQ Based). The objective questions are of 04 marks and for Drawing questions the assigned marks are more than an MCQ one. Paper II is of 390 marks. Candidates were advised to practice an ample number of mocktests to get a vivid idea.
The candidates have to complete each paper 03 hours. There is negative marking in each paper of JEE Main, each occurrence of the wrong answer will deduct 1 mark. There will be no marks for unattempted questions. With the help of this marking scheme and the answer key, a candidate can estimate their scores.
Students can check their ranks of JEE Main 2019 by using various rank predictors available online. These rank predictors generally indicate the rank against JEE Main scores. There are few coaching institutes which provide rank predictors, for instance, Aaksh, Bansal, Career Joint, Allen. The importance of the rank predictors is to get a roundabout idea of the performance of the candidates in JEE Main 2019. However, candidates must not rely totally on the rank predictors as the rank predicted in the JEE Main Rank Predictor goes a notch up or down after the declaration of result.
Last year Maximum and minimum cut off marks for the general category candidates were 350 and 74 respectively. The maximum cut off marks for the candidates belonging to the OBC NCL, SC, ST, and PWD category was the same i.e. 73 and the minimum cut off marks for OBC NCL, SC, ST, and PWD category was 45, 29, 24 and -35 respectively. Total 111275, 65313, 34425, 17256 and 2765 candidates belonging to general, OBC NCL, SC, ST, and PWD category have last year qualified the JEE Main entrance test respectively.
This is the first year of enactment for this autonomous agency. NTA was established to take over the role of the Central Board of Secondary Education(CBSE) and successfully intends to conduct some of the national level exams like JEE Main, UGC NET, NEET, GPAT, and CMAT for the academic session 2019. JEE Main 2019 under the supervision of NTA shall be conducted twice i.e in the month of January and April in online mode across 467 Centres of which 09 centers are outside India.